Q75
For arbitrary matrices E, F, G and H, if EF - FE = 0 then Trace (EFGH) is equal to
A.
Trace (HGFE)
AnswerB.
Trace (E).Trace (F).Trace (G).Trace (H)
C.
Trace (GFEH)
D.
Trace (EGHF)
Answer: Option A
Solution
Answer: Option A
No explanation is given for this question Let's Discuss on Board