m - a^2b^2 + c^2 + m - b^2c^2 + a^2 + m - c^2a^2 + b^2 = 3, then the value of m is?

Answer: Option B

$$\begin{array}{rl}& \frac{m-a^2}{b^2+c^2}+\frac{m-b^2}{c^2+a^2}+\frac{m-c^2}{a^2+b^2}=3\\ & \Rightarrow m=?\\ & \Rightarrow \frac{m-a^2}{b^2+c^2}+\frac{m-b^2}{c^2+a^2}+\frac{m-c^2}{a^2+b^2}=1+1+1\\ & \text{Put }m=a^2+b^2+c^2\text{ from option (B)}\end{array}$$
$$\text{L}\text{.H}\text{.S}\text{. = }\frac{a^2+b^2+c^2-a^2}{b^2+c^2}+$$      $$\frac{a^2+b^2+c^2-b^2}{c^2+a^2}+$$    $$\frac{a^2+b^2+c^2-c^2}{a^2+b^2}$$
$$\begin{array}{rl}& \Rightarrow \frac{b^2+c^2}{b^2+c^2}+\frac{a^2+c^2}{c^2+a^2}+\frac{a^2+b^2}{a^2+b^2}\\ & \Rightarrow 1+1+1=\text{R}\text{.H}\text{.S}\text{.}\\ & \Rightarrow m=a^2+b^2+c^2\end{array}$$