From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 200 m high, the distance of point P from the foot of the tower is:

Answer: Option A

Solution

Answer: Option A

Solution:

$$\begin{array}{rl}& \tan 30^{\circ }=\frac{RQ}{PQ}\\ & \frac{1}{\sqrt{3}}=\frac{200}{PQ}\\ & PQ=200\sqrt{3}\\ & =200\times 1.73\\ & =346\text{m}\end{array}$$