Geeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).

Answer: Option A

Solution

Answer: Option A

Solution:

$$\begin{array}{rl}& \text{Babita’s speed}=1\\ & \text{Geeta’s speed}=\frac{5}{2}\end{array}$$

$$\begin{array}{rl}& \Rightarrow \text{Relative speed in same direction}\\ & =\frac{5}{2}-1=\frac{3}{2}\\ & \Rightarrow \text{Time}=\frac{40}{\frac{3}{2}}=\frac{80}{3}=26.66\\ & \text{Distance travel by Babita}\\ & =1\times 26.66-----26.66\\ & \text{Total distance}=40+26.66\\ & =66.66\\ & =66.67\end{array}$$