Given A = 265 and B = (264 + 263 + 262 + ..... +20), which of the following is true?

Answer: Option D

B is in G.P. with a = 2⁰, r = 2, n = 65
$$\begin{array}{rl}& \therefore S_n=\frac{a\left(r^n-1\right)}{r-1}\\ & =\frac{2^0\left(2^{65}-1\right)}{2-1}\\ & \therefore B=2^{65}-1\\ & \Rightarrow B=A-1\\ & \therefore A\text{is}\text{larger}\text{then}B\text{by}1\end{array}$$