Q345
Given the program of naive method. for i=1 to n do for j=1 to n do Z[i][j]=0; for k=1 to n do ___________________________ Fill in the blanks with appropriate formula
A.
Z[i][j] = Z[i][j] + X[i][k]*Y[k][j]
AnswerB.
Z[i][j] = Z[i][j] + X[i][k] + Y[k][j]
C.
Z[i][j] = Z[i][j] * X[i][k]*Y[k][j]
D.
Z[i][j] = Z[i][j] * X[i][k] + Y[k][j]
Answer: Option A
Solution
Answer: Option A
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