Q3
If 0 ≤ θ ≤ /2 and sec2θ + tan2θ = 7, then θ is
If 0 ≤ θ ≤ and sec2θ + tan2θ = 7, then θ is
A.
radian
B.
radian
AnswerC.
radian
D.
radian
Answer: Option B
Solution
Answer: Option B
Solution:
sec2θ + tan2θ = 71 + tan2θ + tan2θ = 7
2tan2θ = 7 - 1 = 6
tan2θ = 3
tanθ = √3 = tan 60°