If 13 + 23 . . . . . . + 103 = 3025, then the value of 23 + 43 . . . . . . + 203 is:

Answer: Option C

$$\begin{array}{rl}& \because 1^3+2^3+3^3......+10^3=3025\\ & \text{To find}=2^3+4^3+6^3......+20^3=?\\ & \Rightarrow 2^3\left(1^3+2^3+3^3......+{10}^3\right)\\ & \left[{\left(\frac{n\left(n+1\right)}{2}\right)}^2={\left(\frac{10\left(11\right)}{2}\right)}^2={\left(55\right)}^2=3025\right]\\ & \Rightarrow 8\times 3025\\ & \Rightarrow 24200\end{array}$$