If 2 + cos = 7/3 , then the value of ( ta n^2 - ^2 ) is?

Answer: Option B

$$\begin{array}{rl}& \text{2}\sin \theta +\text{cos}\theta =\frac{7}{3}\\ & \Rightarrow \left(\text{ta}{\text{n}}^2\theta -\text{se}{\text{c}}^2\theta \right)\\ & \Rightarrow \left({\sec }^2\theta -1-\text{se}{\text{c}}^2\theta \right)\\ & \left[\because 1+\text{ta}{\text{n}}^2\theta ={\sec }^2\theta \right]\\ & \Rightarrow -1\end{array}$$