If 3x2 - 5x + 1 = 0, then the value of ( x^2 + 19x^2 ) is:

Answer: Option C

$$\begin{array}{rl}& 3x\left(x-\frac{5}{3}+\frac{1}{3x}\right)=0\\ & x+\frac{1}{3x}=\frac{5}{3}\\ & x^2+\frac{1}{9x^2}+\frac{2}{3}=\frac{25}{9}\\ & x^2+\frac{1}{9x^2}=\frac{25-6}{9}\\ & x^2+\frac{1}{9x^2}=\frac{19}{9}\\ & x^2+\frac{1}{9x^2}=2\frac{1}{9}\end{array}$$