If 3x2 - 9x + 3 = 0, then what is the value of ( x + 1/x )^3?

Answer: Option D

$$\begin{array}{rl}& 3x^2-9x+3=0\\ & 3x\left(x-3+\frac{1}{x}\right)=0,x+\frac{1}{x}=3\\ & \therefore {\left(x+\frac{1}{x}\right)}^3={\left(3\right)}^3=27\end{array}$$