If 4^4x + 1 = 164 , then the value of x is?

Answer: Option B

$$\begin{array}{rl}& 4^{4x+1}=\frac{1}{64}\\ & \Rightarrow 4^{4x+1}=\frac{1}{{\left(4\right)}^3}\\ & \Rightarrow 4^{4x+1}={\left(4\right)}^{-3}\\ & \Rightarrow 4x+1=-3\\ & \Rightarrow 4x=-4\\ & \Rightarrow x=-1\end{array}$$