If 64^x + 1 = 644^x , then the value of x is?

Answer: Option B

$$\begin{array}{rl}& 64^{x+1}=\frac{64}{4^x}\\ & \Rightarrow {\left(4^3\right)}^{x+1}-\frac{4^3}{4^x}\\ & \Rightarrow 4^{3x+3}=4^{3-x}\\ & \Rightarrow 3x+3=3-x\\ & \Rightarrow 4x=0\\ & \Rightarrow x=0\end{array}$$