If [8(x + y)3 - 27(x - y)3] ÷ (5y - x) = Ax2 + Bxy + Cy2, then the value of (A + B + C) is:

Answer: Option C

[8(x + y)³ - 27(x - y)³] ÷ (5y - x) = Ax² + Bxy + Cy²
Let, x = 1, y = 1
[8(1 + 1)³ - 27 × 0] ÷ (5 - 1) = (A + B + C)
$$\frac{8\times 8}{4}$$  = A + B + C
16 = A + B + C