If (8x3 - 27y3) ÷ (2x - 3y) = (Ax2 + Bxy + Cy2), then the value of (2A + B - C) is:

Answer: Option C

$$\begin{array}{rl}& \left(8x^3-27y^3\right)÷\left(2x-3y\right)=A{x}^2+Bxy+C{y}^2\\ & \frac{\left(2x-3y\right)\left(4x^2+6xy+9y^2\right)}{\left(2x-3y\right)}=A{x}^2+Bxy+C{y}^2\\ & 4x^2+6xy+9y^2=A{x}^2+Bxy+C{y}^2\\ & \text{Comparison both side}\\ & A=4,B=6,C=9\\ & \left(2A+B-C\right)\\ & =\left(2\times 4+6-9\right)\\ & =5\end{array}$$