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Aptitude · Q403

Number System

Competitive Exams · Aptitude · question 403

Q403

If a and b are positive integers, a > b and (a + b)2 - (a - b)2 > 29 Then the smallest value of a is -

A.
3
B.
4
Answer
C.
6
D.
7

Answer: Option B

Solution

Answer: Option B
Solution:
Since (a + b)2 - (a - b)2 = 4ab, So, the given expression should be a multiple of 4
So, the least value of 4ab is 32 and so the least value of ab is 8
Hence, the smallest value of a is 4 and that of b is 2
Hence, a = 4