If a + b + c = 0, then the value of ( a + bc + b + ca + c + ab ) ( ab + c + bc + a + ca + b ) = \,?

Answer: Option C

a + b + c = 0
Have values
a = 1
b = 2
c = - 3
$$\Rightarrow \left(\frac{a+b}{c}+\frac{b+c}{a}+\frac{c+a}{b}\right)$$     $$\left(\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}\right)$$
$$\Rightarrow \left(\frac{1+2}{-3}+\frac{2-3}{1}+\frac{-3+1}{2}\right)$$     $$\left(\frac{1}{2-3}+\frac{2}{-3+1}+\frac{-3}{1+2}\right)$$
$$\begin{array}{rl}& \Rightarrow \left(-1-1-1\right)\left(-1-1-1\right)\\ & \Rightarrow -3\times -3\\ & \Rightarrow 9\end{array}$$