If A is 40% less than B and C is 40% of the sum of A and B, then by what percentage is B greater than C?

Answer: Option B

Solution

Answer: Option B

Solution:

$$\begin{array}{rl}& \text{C}=\left(\text{A}+\text{B}\right)\times 40\%\\ & =\frac{160\times 40}{100}\\ & =64\\ & \text{B is more than C}\\ & =\frac{36}{64}\times 100\\ & =56\frac{1}{4}\%\end{array}$$