If a^2 + 2a^2 = 16, then find the value of 72a^2a^4 + 2 + 8a^2.

Answer: Option A

$$\begin{array}{rl}& a^2+\frac{2}{a^2}=16\\ & \frac{72a^2}{a^4+2+8a^2}\\ & =\frac{72}{a^2+\frac{2}{a^2}+8}\\ & =\frac{72}{16+8}\\ & =3\end{array}$$