If A = tan11°. tan29°, B = 2cot61°. cot79° then -

Answer: Option C

$$\begin{array}{rl}& \iff \frac{\text{A}}{\text{B}}=\frac{\text{tan1}{\text{1}}^{\circ }\text{.tan2}{\text{9}}^{\circ }}{\text{2cot}{61}^{\circ }.\cot {79}^{\circ }}\\ & \iff \frac{\text{A}}{\text{B}}=\frac{\text{tan1}{\text{1}}^{\circ }\text{.tan2}{\text{9}}^{\circ }}{\text{2}\left[\text{cot}\left({90}^{\circ }-{29}^{\circ }\right).\cot \left({90}^{\circ }-{11}^{\circ }\right)\right]}\\ & \iff \frac{\text{A}}{\text{B}}=\frac{\text{tan1}{\text{1}}^{\circ }\text{.tan2}{\text{9}}^{\circ }}{\text{2tan1}{\text{1}}^{\circ }.tan{29}^{\circ }}\\ & \iff \frac{\text{A}}{\text{B}}=\frac{1}{2}\\ & \iff 2\text{A}=\text{B}\end{array}$$