If = 2p1 + p^2, then tanθ is equal to:

Answer: Option D

$$\begin{array}{rl}& \cos \theta =\frac{2p}{1+p^2}\\ & A{B}^2={\left(1+p^2\right)}^2-{\left(2p\right)}^2\\ & AB=1-p^2\\ & \tan \theta =\frac{1-p^2}{2p}\end{array}$$