If 4x - 3x + 4y - 3y + 4z - 3z = 0 , then the value of 1/x + 1/y + 1/z is?

Answer: Option C

$$\begin{array}{rl}& \frac{4x-3}{x}+\frac{4y-3}{y}+\frac{4z-3}{z}=0\\ & \Rightarrow \frac{4x}{x}-\frac{3}{x}+\frac{4y}{y}-\frac{3}{y}+\frac{4z}{z}-\frac{3}{z}=0\\ & \Rightarrow 4-\frac{3}{x}+4-\frac{3}{y}+4-\frac{3}{z}=0\\ & \Rightarrow 12-3\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)=0\\ & \Rightarrow -3\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)=-12\\ & \Rightarrow \frac{1}{x}+\frac{1}{y}+\frac{1}{z}=4\end{array}$$