If in a triangle ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and ADBD = 3/5 . If AC = 4 cm, then AE is

Answer: Option A

According to question,

Given :
AD = 3
BD = 5
AB = 8
AC = 4
AE = ?
By applying B. P. T
$$\begin{array}{rl}& \frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}\\ & \frac{3}{8}=\frac{AE}{4}\\ & AE=\frac{3}{2}=1.5\text{cm}\end{array}$$