If in the following figure (not to scale), ∠DAB + ∠CBA = 90°, BC = AD, AB = 20 cm, CD = 10 cm then the area of the quadrilateral ABCD is:

If in the following figure (not to scale), ∠DAB + ∠CBA = 90°, BC = AD, AB = 20 cm, CD = 10 cm then the area of the quadrilateral ABCD is:

Answer: Option D

Solution

Answer: Option D

Solution:

$$\text{Area of ABCD}=\frac{1}{2}\times 30\times 5=75\text{ c}{\text{m}}^2$$