Q51
If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is
A.
-2
B.
3
AnswerC.
-3
D.
6
Answer: Option B
Solution
Answer: Option B
Solution:
(2K - 1) - K = (2K + 1) - (2K - 1)2K - 1 - K = 2
⇒ K = 3