If 2 = 0.30103, the number of digits in 4^50 is -

Answer: Option B

$$\begin{array}{rl}& \log 4^{50}\\ & =50\log 4\\ & =50\log 2^2\\ & =\left(50\times 2\right)\log 2\\ & =100\times \log 2\\ & =\left(100\times 0.30103\right)\\ & =30.103\\ & \therefore \text{characteristic}=30,\end{array}$$
Hence, the number of digits in $${\text{4}}^{50}=31$$