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Aptitude · Q163

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Competitive Exams · Aptitude · question 163

Q163

If M = 0.1 + (0.1)2 + (0.01)2 and N = 0.3 + (0.03)2 + (0.003)2, then what is the value of M + N?

A.
0.411009
Answer
B.
0.413131
C.
0.313131
D.
0.131313

Answer: Option A

Solution

Answer: Option A
Solution:
M = 0.1 + (0.1)2 + (0.01)2
N = 0.3 + (0.03)2 + (0.003)2
M + N = 0.1 + (0.1)2 + (0.01)2 + (0.3) + (3 × 0.01)2 + (3 × 0.001)2
= 0.1 + (0.1)2 + (0.01)2 + 0.3 + 9 × (0.01)2 + 9 × (0.001)2
= 0.4 + (0.1)2 + 10 × (0.01)2 + 9 × (0.001)2
= 0.4 + 0.01 + 0.001 + 0.000009
= 0.411009