Q503
If n is a natural number and n = p_1^x_1 p_2^x_2 p_3^x_3 where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is :
If n is a natural number and n = where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is :
A.
B.
Answer
C.
D.
None of these
Answer: Option B
Solution
Answer: Option B
Solution:
Given n = Where p1, p2, p3 are distinct prime factors
Number of prime factors form :
= (x1 × x2 × x3)
= x1 x2 x3
Hence option (B) is correct