If p = 99, then the value of p(p2 + 3p + 3) is?

Answer: Option B

$$\begin{array}{rl}& \because p=99\\ & p\left(p^2+3p+3\right)\\ & =p^3+3p^2+3p+1-1\\ & ={\left(p+1\right)}^3-1\\ & ={\left(99+1\right)}^3-1\\ & ={\left(100\right)}^3-1\\ & =1000000-1\\ & =999999\end{array}$$