If p3 - q3 = (p - q)(p + q)2 - xpq, then the value of x is?

Answer: Option A

$$p^3-q^3=\left(p-q\right)\left\{p^2+q^2+pq\right\}$$
$$\Rightarrow \left(p-q\right)\left\{{\left(p+q\right)}^2-xpq\right\}=$$       $$\left(p-q\right)$$ $$\left(p^2+q^2+pq\right)$$
$$\begin{array}{rl}& \Rightarrow p^2+q^2+2pq-xpq=p^2+q^2+pq\\ & \Rightarrow 2pq-pq=xpq\\ & \Rightarrow pq=xpq\\ & \Rightarrow x=1\end{array}$$