If p3 - q3 = (p - q)(p -q)2 + xpq, then the value of x is?

Answer: Option C

$$\begin{array}{rl}& \Rightarrow p^3-q^3=\left(p-q\right)\left\{{\left(p-q\right)}^2+xpq\right\}\\ & \Rightarrow \left(p-q\right)\left\{p^2+q^2+pq\right\}=\left(p-q\right)\left\{p^2+q^2-2pq+xpq\right\}\\ & \Rightarrow p^2+q^2+pq=p^2+q^2-2pq+xpq\\ & \Rightarrow 3pq=xpq\\ & \Rightarrow x=3\end{array}$$