If p/a + q/b + r/c = 1 and a/p + b/q + c/r = 0 where a, b, c, p, q, r…

Question

If p/a + q/b + r/c = 1 and a/p + b/q + c/r = 0 where a, b, c, p, q, r are non-zero real numbers, then p^2a^2 + q^2b^2 + r^2c^2 is equal to = ?

Accepted Answer

Option B. 1. Answer & Solution Answer: Option B Solution: & a/p + b/q + c/r = 0\,\,\,\, & aqr + bpr + cpq = 0....( i) & p/a + q/b + r/c = 1\,\, & ( p/a + q/b + r/c )^2 = 1 & p^2a^2 + q^2b^2 + r^2c^2\, + 2 ( pqab + prac + qrbc ) = 1 & p^2a^2 + q^2b^2 + r^2c^2 + 2 ( pqc + prb + qra )abc = 1 &…