If secα + tanα = 2, then the value of sinα is (assume that 0 < α < 90°)

Answer: Option C

$$\begin{array}{rl}& sec\alpha +\tan \alpha =2.....(i)\\ & sec\alpha -\tan \alpha =\frac{1}{2}.....(ii)\\ & \text{Adding equation (i) and (ii)}\\ & \text{2sec}\alpha =2+\frac{1}{2}\\ & \sec \alpha =\frac{5\to \text{H}}{4\to \text{B}}\end{array}$$

$$\sin \alpha =\frac{3}{5}=0.6$$