If sinθ = 941, 0° < θ < 90° then what is the value of cotθ?

Answer: Option C

$$\begin{array}{rl}& \sin \theta =\frac{9}{41}\\ & \frac{P}{H}=\frac{9}{41},B=40\\ & \Rightarrow \cot \theta =\frac{B}{P}=\frac{40}{9}\end{array}$$