If sinθ × cosθ = 1/2 , Then the value of sinθ - cosθ is where 0° < θ < 90°.

Answer: Option A

$$\begin{array}{rl}& \sin \theta \times \cos \theta =\frac{1}{2}\\ & \text{Multiply by 2 both side}\\ & 2\sin \theta \times \cos \theta =1\\ & \sin 2\theta =1\\ & \sin 2\theta =\sin 90^{\circ }\\ & 2\theta =90^{\circ }\\ & \theta =45^{\circ }\\ & \text{So,}\sin \theta -\text{cos}\theta \\ & =\sin 45^{\circ }-\cos 45^{\circ }\\ & =\frac{1}{\sqrt{2}}-\frac{1}{\sqrt{2}}\\ & =0\end{array}$$