If sinθ + cosθ = 2 sin(90° - θ) then the value of cotθ is?

Answer: Option B

$$\begin{array}{rl}& \sin \theta +\cos \theta =\sqrt{2}\sin \left({90}^{\circ }-\theta \right)\\ & \sin \theta +\cos \theta =\sqrt{2}cos\theta \\ & \text{Divide both sides by cos}\theta \\ & \text{tan}\theta +1=\sqrt{2}\\ & \cot \theta =\frac{1}{\sqrt{2}-1}\\ & =\sqrt{2}+1\end{array}$$