If sin 3A = cos(A - 26°), where 3A is an acute angle then the value of A is?

Answer: Option A

$$\begin{array}{rl}& \Rightarrow \text{sin 3A}=\text{cos}\left(\text{A}-{26}^{\circ }\right)\\ & \Rightarrow \text{3A + A}-\text{2}{\text{6}}^{\circ }\text{ = }90^{\circ }\\ & \left[\text{If sin A}=\text{cos B}\text{. then, A}+\text{B}={90}^{\circ }\right]\\ & \Rightarrow 4\text{A = 11}{6}^{\circ }\\ & \Rightarrow \text{A}=29^{\circ }\end{array}$$