If = a a^2 + b^2 , 0° < θ < 90°, then the value of secθ + tanθ is:

Aptitude · Q206

Trigonometry

Competitive Exams · Aptitude · question 206

Q206

sin θ = \frac{a}{a ^{2} + b ^{2}},

0° < θ < 90°, then the value of secθ + tanθ is:

\frac{a ^{2} + b ^{2} + a}{b}

Answer

\frac{a ^{2} + b ^{2} + b}{2 a}

\frac{a ^{2} + b ^{2} + a}{2 b}

\frac{a ^{2} + b ^{2} + b}{a}

Answer: Option A

Answer: Option A

Solution:

sin θ = \frac{a}{a ^{2} + b ^{2}}

sec θ + tan θ = \frac{a ^{2} + b ^{2}}{b} + \frac{a}{b} = \frac{a ^{2} + b ^{2} + a}{b}