If \, 1 + x/9 = 133 , then the value of x is?

Answer: Option B

$$\begin{array}{rl}& \sqrt{1+\frac{x}{9}}=\frac{13}{3}\\ & \text{By option }\\ & \text{Put }x=160\\ & \sqrt{1+\frac{160}{9}}=\frac{13}{3}\\ & \Rightarrow \sqrt{\frac{169}{9}}=\frac{13}{3}\\ & \Rightarrow \frac{13}{3}=\frac{13}{3}\\ & \\ & \mathbf{Alternate}:\\ & \text{Squaring both sides}\\ & {\left(\sqrt{1+\frac{x}{9}}\right)}^2={\left(\frac{13}{3}\right)}^2\\ & \Rightarrow 1+\frac{x}{9}=\frac{169}{9}\\ & \Rightarrow \frac{9+x}{9}=\frac{169}{9}\\ & \Rightarrow 9+x=169\\ & \Rightarrow \boxed{x=160}\end{array}$$