If tan = 2, then the value of cose c^2 - se c^2 cose c^2 + sec^2 is?

Answer: Option C

$$\begin{array}{rl}& \text{tan}\alpha =2\left(\text{given}\right)\\ & \therefore \frac{\text{cose}{\text{c}}^2\alpha -\text{se}{\text{c}}^2\alpha }{\text{cose}{\text{c}}^2\alpha +se{c}^2\alpha }\end{array}$$
(Divide by coses²α both in N and D)
$$\begin{array}{rl}& =\frac{1-\text{ta}{\text{n}}^2\alpha }{1+\text{ta}{\text{n}}^2\alpha }\\ & =\frac{1-{\left(2\right)}^2}{1+{\left(2\right)}^2}\\ & =-\frac{3}{5}\end{array}$$