If tan θ = 1, then the value of 8 + 5 ^3 - 2 ^3 + 7 is?

Answer: Option A

$$\begin{array}{rl}& \text{If }\tan \theta =1\\ & \text{It means }\theta =45^{\circ }\\ & =\frac{8\sin \theta +5\cos \theta }{{\sin }^3\theta -2{\cos }^3\theta +7\cos \theta }\\ & =\frac{8\sin {45}^{\circ }+5\cos {45}^{\circ }}{{\sin }^3{45}^{\circ }-2{\cos }^3{45}^{\circ }+7\cos {45}^{\circ }}\\ & =\frac{8\times \frac{1}{\sqrt{2}}+5\times \frac{1}{\sqrt{2}}}{{\left(\frac{1}{\sqrt{2}}\right)}^3-2{\left(\frac{1}{\sqrt{2}}\right)}^3+7\left(\frac{1}{\sqrt{2}}\right)}\\ & =2\end{array}$$