1c:I[1254,["7330","static/chunks/d3ac728e-78c3d5d7a486ed3a.js","5159","static/chunks/5159-48592f0bf1a47f9d.js","8175","static/chunks/8175-f84d59b9bd013e10.js","8167","static/chunks/8167-b25693a0140130f2.js","664","static/chunks/664-bceb0f356f9312eb.js","3703","static/chunks/app/practice-question/%5Bslug%5D/page-d1408559b663b83f.js"],"PracticeQuestionCard"] 1b:T4d6,{"@context":"https://schema.org","@type":"QAPage","name":"If tan2α = 1 + 2tan2β (α, β are positive acute angles), then √2cosα -…","url":"https://vidyalelo.com/practice-question/if-tan2%CE%B1-1-2tan2%CE%B2-%CE%B1-%CE%B2-are-positive-acute-angles-then-square-root-of-2cos%CE%B1-cos%CE%B2-is-equal-to-93636","keywords":"practice questions, MCQ, MCQs with answers, objective questions, competitive exam questions, Competitive Exams, Competitive Exams MCQ, Competitive Exams MCQs, Competitive Exams questions, Competitive Exams practice questions, Aptitude, Aptitude MCQ, Aptitude MCQs, Aptitude questions, Aptitude practice questions, Trigonometry","mainEntity":{"@type":"Question","name":"If tan2α = 1 + 2tan2β (α, β are positive acute angles), then √2cosα -…","text":"If tan2α = 1 + 2tan2β (α, β are positive acute angles), then √2cosα - cosβ is equal to?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"Option A. 0. Answer & Solution Answer: Option A Solution: & ta n^2 = 1 + 2 ta n^2 & se c^2 - 1 = 1 + 2 ( se c^2 - 1 ) & ^2 - 1 = 2 ^2 - 1 & 1 co s^2 = 2 co s^2 & 2 cos = cos & 2 cos - cos = 0 & & Alternate: & ta n^2 = 1 + 2 ta n^2 & Put = 45^ & ta n^2 = 1 + 2. ta n^245^ & ta n^2 = 3 & tan =…"}}}1d:T6de,

Answer & Solution

Answer: Option A

Solution:

$$\eqalign{ & {\text{ ta}}{{\text{n}}^2}\alpha = 1 + 2{\text{ta}}{{\text{n}}^