If the given figure, in a right angle triangle ABC, AB = 12 cm and AC = 15 cm. A square is inscribed in the triangle. One of the vertices of square coincides with the vertex of triangle. What is the maximum possible area (in cm2) of the square?

If the given figure, in a right angle triangle ABC, AB = 12 cm and AC = 15 cm. A square is inscribed in the triangle. One of the vertices of square coincides with the vertex of triangle. What is the maximum possible area (in cm²) of the square?

Answer: Option A

Solution

Answer: Option A

Solution:

Then BC = 9 cm
Side (a) square $$=\frac{12\times 9}{21}=\frac{36}{7}$$
Area of largest square that can be formed inside the circle $$={\left(\frac{36}{7}\right)}^2=\frac{1296}{49}$$