If the product of three consecutive integers is 120, then the sum of the integers is :

Answer: Option D

$$\begin{array}{rl}& 120:\\ & =2\times 2\times 2\times 3\times 5\\ & =\left(2\times 2\right)\times 5\times \left(2\times 3\right)\\ & =4\times 5\times 6\end{array}$$
Clearly, the three consecutive integers whose product is 120 are 4, 5 and 6
Required sum :
= 4 + 5 + 6
= 15