If the square of sum of three positive consecutive natural number exceeds the sum of their squares by 292, then what is the largest of the three number?

Answer: Option D

Go through option
[(x + 2) + (x + 1) + x]² = [(x + 2)² + (x + 1)² + x²] + 292
Let x = 3
(5 + 4 + 3)² = 25 + 16 + 9 + 292
144 < 342
Option D, x = 6
(8 + 7 + 6)² = 64 + 49 + 36 + 292
441 = 441
∴ Option D satisfy this equation
So, largest is 8.