If two numbers are respectively 30% and 40% more than a third number, what percent is the first of the second?

Answer: Option A

Let the third number be 100. Then,
1^st number = 130
2^nd number = 140
% 1^st number to the 2^nd number
$$\begin{array}{rl}& =\frac{130\times 100}{140}\\ & =\frac{650}{7}\\ & =92\frac{6}{7}\%\end{array}$$