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Aptitude · Q401

Algebra

Competitive Exams · Aptitude · question 401

Q401

If x + 1/x = 1, then the value of x12 + x9 + x6 + x3 + 1 is:

If   then the value of x12 + x9 + x6 + x3 + 1 is:
A.
1
Answer
B.
-1
C.
0
D.
-2

Answer: Option A

Solution

Answer: Option A
Solution:

x2 + 1 - x = 0
(x + 1)(x2 + 12 - x) = 0
x3 + 1 = 0
x3 = -1
⇒ x12 + x9 + x6 + x3 + 1
= 1 - 1 + 1 - 1 + 1
= 1