If x = 2, y = 1 and z = -3, then x3 + y3 + z3 - 3xyz is equal to?

Answer: Option B

$$\begin{array}{rl}& \text{According to the question,}\\ & x=2,y=1,z=-3\\ & x^3+y^3+z^3-3xyz=?\\ & \text{As we know that}\\ & a+b+c=0\text{ then }{a}^3+b^3+c^3-3abc=0\\ & 2+1-3=0\\ & \therefore x^3+y^3+z^3-3xyz=0\end{array}$$