If x = 222, y = 223, z = 225, then the value of x3 + y3 + z3 - 3xyz is?

Answer: Option B

$$x^3+y^3+z^3-3xyz$$
$$=\frac{1}{2}\left(x+y+z\right)$$  $$\left[{\left(x-y\right)}^2+{\left(y-z\right)}^2+{\left(z-x\right)}^2\right]$$
$$=\frac{1}{2}\left(222+223+225\right)$$    $$\left[{\left(222-223\right)}^2+{\left(223-225\right)}^2+{\left(225-222\right)}^2\right]$$
$$\begin{array}{rl}& =\frac{1}{2}\left(670\right)\left(1+4+9\right)\\ & =\frac{1}{2}\times 670\times 14\\ & =4690\end{array}$$