If x = 3 + 2√2, then the value of x^2 + 1x^2 is:

Answer: Option D

$$\begin{array}{rl}& x=3+2\sqrt{2}\\ & \frac{1}{x}=3-2\sqrt{2}\\ & x+\frac{1}{x}=6\\ & x^2+\frac{1}{x^2}={\left(6\right)}^2-2\\ & x^2+\frac{1}{x^2}=34\end{array}$$